Есть такая проблема: при использовании функции mysql_num_rows() вылезает следующая ошибка:
Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in C:\Program Files\Apache Group\Apache2\htdocs\something.php on line 7.
<? mysql_pconnect("localhost", "root", ""); mysql_select_db("something"); $request = "select * from something"; $result = mysql_query($request); echo $result; $rows = mysql_num_rows($result); ?> <table align="center" border="1" cellpadding ="2" cellspacing ="0" bordercolor="#000066"> <tr> <th>something 1</th> <th>something 2</th> <th>something 3</th> <th>something 4</th> </tr> <? for ($i=0; $i<$rows; $i++) { $r=mysql_fetch_array($result); $rm=chunk_split($r["something_4"]); $rm=nl2br($rm); ?> <tr> <td><?=$r["something_1"]?> </td> <td><b><? echo $r["something_2"] ?></b></td> <td><? echo $r["something_3"]." ";?></td> <td><?=$rm?></td> </tr> <?}?> </table>В чем могуть быть грабли?